Tin Can N contains 50-cent coins and Tin Can P contains 10-cent coins. There are 14 more coins in Tin Can P than in Tin Can N. The amount of money in Tin Can N is 500¢ more than the amount of money in Tin Can P. How many total coins are there?
| |
Tin Can N |
Tin Can P |
| Number |
1 u |
1 u + 14 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 140 |
Total value of 50¢ coins in Tin Can N
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Tin Can P
= 10 x (1 u + 14)
= 10 u + 140
The amount in Tin Can N is 500¢ more than Tin Can P. If another 500¢ is added into Tin Can P, both Tin Can N and Tin Can P will have the same amounts of money.
50 u = 10 u + 140 + 500
50 u - 10 u = 140 + 500
40 u = 640
1 u = 640 ÷ 40 = 16
Total number of coins
= 1 u + (1 u + 14)
= 2 u + 14
= 2 x 16 + 14
= 32 + 14
= 46
Answer(s): 46
