Jar D contains 50-cent coins and Jar E contains 5-cent coins. There are 12 more coins in Jar E than in Jar D. The amount of money in Jar D is 480¢ more than the amount of money in Jar E. How many total coins are there?
|
Jar D |
Jar E |
Number |
1 u |
1 u + 12 |
Value |
50¢ |
5¢ |
Total value |
50 u |
5 u + 60 |
Total value of 50¢ coins in Jar D
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar E
= 5 x (1 u + 12)
= 5 u + 60
The amount in Jar D is 480¢ more than Jar E. If another 480¢ is added into Jar E, both Jar D and Jar E will have the same amounts of money.
50 u = 5 u + 60 + 480
50 u - 5 u = 60 + 480
45 u = 540
1 u = 540 ÷ 45 = 12
Total number of coins
= 1 u + (1 u + 12)
= 2 u + 12
= 2 x 12 + 12
= 24 + 12
= 36
Answer(s): 36