Bottle A contains 50-cent coins and Bottle B contains 5-cent coins. There are 25 more coins in Bottle B than in Bottle A. The amount of money in Bottle A is 1000¢ more than the amount of money in Bottle B. How many total coins are there?
|
Bottle A |
Bottle B |
Number |
1 u |
1 u + 25 |
Value |
50¢ |
5¢ |
Total value |
50 u |
5 u + 125 |
Total value of 50¢ coins in Bottle A
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Bottle B
= 5 x (1 u + 25)
= 5 u + 125
The amount in Bottle A is 1000¢ more than Bottle B. If another 1000¢ is added into Bottle B, both Bottle A and Bottle B will have the same amounts of money.
50 u = 5 u + 125 + 1000
50 u - 5 u = 125 + 1000
45 u = 1125
1 u = 1125 ÷ 45 = 25
Total number of coins
= 1 u + (1 u + 25)
= 2 u + 25
= 2 x 25 + 25
= 50 + 25
= 75
Answer(s): 75