Coin Box T contains 50-cent coins and Coin Box U contains 10-cent coins. There are 11 more coins in Coin Box U than in Coin Box T. The amount of money in Coin Box T is 930¢ more than the amount of money in Coin Box U. How many total coins are there?
| |
Coin Box T |
Coin Box U |
| Number |
1 u |
1 u + 11 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 110 |
Total value of 50¢ coins in Coin Box T
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Coin Box U
= 10 x (1 u + 11)
= 10 u + 110
The amount in Coin Box T is 930¢ more than Coin Box U. If another 930¢ is added into Coin Box U, both Coin Box T and Coin Box U will have the same amounts of money.
50 u = 10 u + 110 + 930
50 u - 10 u = 110 + 930
40 u = 1040
1 u = 1040 ÷ 40 = 26
Total number of coins
= 1 u + (1 u + 11)
= 2 u + 11
= 2 x 26 + 11
= 52 + 11
= 63
Answer(s): 63
