Bag T contains 50-cent coins and Bag U contains 10-cent coins. There are 10 more coins in Bag U than in Bag T. The amount of money in Bag T is 820¢ more than the amount of money in Bag U. How many total coins are there?
| |
Bag T |
Bag U |
| Number |
1 u |
1 u + 10 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 100 |
Total value of 50¢ coins in Bag T
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Bag U
= 10 x (1 u + 10)
= 10 u + 100
The amount in Bag T is 820¢ more than Bag U. If another 820¢ is added into Bag U, both Bag T and Bag U will have the same amounts of money.
50 u = 10 u + 100 + 820
50 u - 10 u = 100 + 820
40 u = 920
1 u = 920 ÷ 40 = 23
Total number of coins
= 1 u + (1 u + 10)
= 2 u + 10
= 2 x 23 + 10
= 46 + 10
= 56
Answer(s): 56
