Jar T contains 50-cent coins and Jar U contains 5-cent coins. There are 34 more coins in Jar U than in Jar T. The amount of money in Jar T is 325¢ more than the amount of money in Jar U. How many total coins are there?
| |
Jar T |
Jar U |
| Number |
1 u |
1 u + 34 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 170 |
Total value of 50¢ coins in Jar T
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar U
= 5 x (1 u + 34)
= 5 u + 170
The amount in Jar T is 325¢ more than Jar U. If another 325¢ is added into Jar U, both Jar T and Jar U will have the same amounts of money.
50 u = 5 u + 170 + 325
50 u - 5 u = 170 + 325
45 u = 495
1 u = 495 ÷ 45 = 11
Total number of coins
= 1 u + (1 u + 34)
= 2 u + 34
= 2 x 11 + 34
= 22 + 34
= 56
Answer(s): 56
