Coin Box W contains 50-cent coins and Coin Box X contains 10-cent coins. There are 28 more coins in Coin Box X than in Coin Box W. The amount of money in Coin Box W is 520¢ more than the amount of money in Coin Box X. How many total coins are there?
| |
Coin Box W |
Coin Box X |
| Number |
1 u |
1 u + 28 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 280 |
Total value of 50¢ coins in Coin Box W
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Coin Box X
= 10 x (1 u + 28)
= 10 u + 280
The amount in Coin Box W is 520¢ more than Coin Box X. If another 520¢ is added into Coin Box X, both Coin Box W and Coin Box X will have the same amounts of money.
50 u = 10 u + 280 + 520
50 u - 10 u = 280 + 520
40 u = 800
1 u = 800 ÷ 40 = 20
Total number of coins
= 1 u + (1 u + 28)
= 2 u + 28
= 2 x 20 + 28
= 40 + 28
= 68
Answer(s): 68
