Jar P contains 50-cent coins and Jar Q contains 20-cent coins. There are 14 more coins in Jar Q than in Jar P. The amount of money in Jar P is 350¢ more than the amount of money in Jar Q. How many total coins are there?
|
Jar P |
Jar Q |
Number |
1 u |
1 u + 14 |
Value |
50¢ |
20¢ |
Total value |
50 u |
20 u + 280 |
Total value of 50¢ coins in Jar P
= 50 x 1 u
= 50 u
Total value of 20¢ coins in Jar Q
= 20 x (1 u + 14)
= 20 u + 280
The amount in Jar P is 350¢ more than Jar Q. If another 350¢ is added into Jar Q, both Jar P and Jar Q will have the same amounts of money.
50 u = 20 u + 280 + 350
50 u - 20 u = 280 + 350
30 u = 630
1 u = 630 ÷ 30 = 21
Total number of coins
= 1 u + (1 u + 14)
= 2 u + 14
= 2 x 21 + 14
= 42 + 14
= 56
Answer(s): 56