Bottle B contains 50-cent coins and Bottle C contains 10-cent coins. There are 26 more coins in Bottle C than in Bottle B. The amount of money in Bottle B is 180¢ more than the amount of money in Bottle C. How many total coins are there?
| |
Bottle B |
Bottle C |
| Number |
1 u |
1 u + 26 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 260 |
Total value of 50¢ coins in Bottle B
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Bottle C
= 10 x (1 u + 26)
= 10 u + 260
The amount in Bottle B is 180¢ more than Bottle C. If another 180¢ is added into Bottle C, both Bottle B and Bottle C will have the same amounts of money.
50 u = 10 u + 260 + 180
50 u - 10 u = 260 + 180
40 u = 440
1 u = 440 ÷ 40 = 11
Total number of coins
= 1 u + (1 u + 26)
= 2 u + 26
= 2 x 11 + 26
= 22 + 26
= 48
Answer(s): 48
