Bag B contains 50-cent coins and Bag C contains 10-cent coins. There are 19 more coins in Bag C than in Bag B. The amount of money in Bag B is 970¢ more than the amount of money in Bag C. How many total coins are there?
|
Bag B |
Bag C |
Number |
1 u |
1 u + 19 |
Value |
50¢ |
10¢ |
Total value |
50 u |
10 u + 190 |
Total value of 50¢ coins in Bag B
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Bag C
= 10 x (1 u + 19)
= 10 u + 190
The amount in Bag B is 970¢ more than Bag C. If another 970¢ is added into Bag C, both Bag B and Bag C will have the same amounts of money.
50 u = 10 u + 190 + 970
50 u - 10 u = 190 + 970
40 u = 1160
1 u = 1160 ÷ 40 = 29
Total number of coins
= 1 u + (1 u + 19)
= 2 u + 19
= 2 x 29 + 19
= 58 + 19
= 77
Answer(s): 77