Tin Can D contains 20-cent coins and Tin Can E contains 10-cent coins. There are 14 more coins in Tin Can E than in Tin Can D. The amount of money in Tin Can D is 40¢ more than the amount of money in Tin Can E. How many total coins are there?
| |
Tin Can D |
Tin Can E |
| Number |
1 u |
1 u + 14 |
| Value |
20¢ |
10¢ |
| Total value |
20 u |
10 u + 140 |
Total value of 20¢ coins in Tin Can D
= 20 x 1 u
= 20 u
Total value of 10¢ coins in Tin Can E
= 10 x (1 u + 14)
= 10 u + 140
The amount in Tin Can D is 40¢ more than Tin Can E. If another 40¢ is added into Tin Can E, both Tin Can D and Tin Can E will have the same amounts of money.
20 u = 10 u + 140 + 40
20 u - 10 u = 140 + 40
10 u = 180
1 u = 180 ÷ 10 = 18
Total number of coins
= 1 u + (1 u + 14)
= 2 u + 14
= 2 x 18 + 14
= 36 + 14
= 50
Answer(s): 50
