Jar C contains 50-cent coins and Jar D contains 5-cent coins. There are 38 more coins in Jar D than in Jar C. The amount of money in Jar C is 935¢ more than the amount of money in Jar D. How many total coins are there?
| |
Jar C |
Jar D |
| Number |
1 u |
1 u + 38 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 190 |
Total value of 50¢ coins in Jar C
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar D
= 5 x (1 u + 38)
= 5 u + 190
The amount in Jar C is 935¢ more than Jar D. If another 935¢ is added into Jar D, both Jar C and Jar D will have the same amounts of money.
50 u = 5 u + 190 + 935
50 u - 5 u = 190 + 935
45 u = 1125
1 u = 1125 ÷ 45 = 25
Total number of coins
= 1 u + (1 u + 38)
= 2 u + 38
= 2 x 25 + 38
= 50 + 38
= 88
Answer(s): 88
