Jar G contains 50-cent coins and Jar H contains 10-cent coins. There are 32 more coins in Jar H than in Jar G. The amount of money in Jar G is 440¢ more than the amount of money in Jar H. How many total coins are there?
| |
Jar G |
Jar H |
| Number |
1 u |
1 u + 32 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 320 |
Total value of 50¢ coins in Jar G
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Jar H
= 10 x (1 u + 32)
= 10 u + 320
The amount in Jar G is 440¢ more than Jar H. If another 440¢ is added into Jar H, both Jar G and Jar H will have the same amounts of money.
50 u = 10 u + 320 + 440
50 u - 10 u = 320 + 440
40 u = 760
1 u = 760 ÷ 40 = 19
Total number of coins
= 1 u + (1 u + 32)
= 2 u + 32
= 2 x 19 + 32
= 38 + 32
= 70
Answer(s): 70
