Jar V contains 50-cent coins and Jar W contains 10-cent coins. There are 18 more coins in Jar W than in Jar V. The amount of money in Jar V is 940¢ more than the amount of money in Jar W. How many total coins are there?
| |
Jar V |
Jar W |
| Number |
1 u |
1 u + 18 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 180 |
Total value of 50¢ coins in Jar V
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Jar W
= 10 x (1 u + 18)
= 10 u + 180
The amount in Jar V is 940¢ more than Jar W. If another 940¢ is added into Jar W, both Jar V and Jar W will have the same amounts of money.
50 u = 10 u + 180 + 940
50 u - 10 u = 180 + 940
40 u = 1120
1 u = 1120 ÷ 40 = 28
Total number of coins
= 1 u + (1 u + 18)
= 2 u + 18
= 2 x 28 + 18
= 56 + 18
= 74
Answer(s): 74
