Coin Box N contains 50-cent coins and Coin Box P contains 5-cent coins. There are 11 more coins in Coin Box P than in Coin Box N. The amount of money in Coin Box N is 1205¢ more than the amount of money in Coin Box P. How many total coins are there?
| |
Coin Box N |
Coin Box P |
| Number |
1 u |
1 u + 11 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 55 |
Total value of 50¢ coins in Coin Box N
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Coin Box P
= 5 x (1 u + 11)
= 5 u + 55
The amount in Coin Box N is 1205¢ more than Coin Box P. If another 1205¢ is added into Coin Box P, both Coin Box N and Coin Box P will have the same amounts of money.
50 u = 5 u + 55 + 1205
50 u - 5 u = 55 + 1205
45 u = 1260
1 u = 1260 ÷ 45 = 28
Total number of coins
= 1 u + (1 u + 11)
= 2 u + 11
= 2 x 28 + 11
= 56 + 11
= 67
Answer(s): 67
