Bag B contains 50-cent coins and Bag C contains 5-cent coins. There are 36 more coins in Bag C than in Bag B. The amount of money in Bag B is 315¢ more than the amount of money in Bag C. How many total coins are there?
| |
Bag B |
Bag C |
| Number |
1 u |
1 u + 36 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 180 |
Total value of 50¢ coins in Bag B
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Bag C
= 5 x (1 u + 36)
= 5 u + 180
The amount in Bag B is 315¢ more than Bag C. If another 315¢ is added into Bag C, both Bag B and Bag C will have the same amounts of money.
50 u = 5 u + 180 + 315
50 u - 5 u = 180 + 315
45 u = 495
1 u = 495 ÷ 45 = 11
Total number of coins
= 1 u + (1 u + 36)
= 2 u + 36
= 2 x 11 + 36
= 22 + 36
= 58
Answer(s): 58
