Bottle W contains 50-cent coins and Bottle X contains 5-cent coins. There are 30 more coins in Bottle X than in Bottle W. The amount of money in Bottle W is 345¢ more than the amount of money in Bottle X. How many total coins are there?
| |
Bottle W |
Bottle X |
| Number |
1 u |
1 u + 30 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 150 |
Total value of 50¢ coins in Bottle W
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Bottle X
= 5 x (1 u + 30)
= 5 u + 150
The amount in Bottle W is 345¢ more than Bottle X. If another 345¢ is added into Bottle X, both Bottle W and Bottle X will have the same amounts of money.
50 u = 5 u + 150 + 345
50 u - 5 u = 150 + 345
45 u = 495
1 u = 495 ÷ 45 = 11
Total number of coins
= 1 u + (1 u + 30)
= 2 u + 30
= 2 x 11 + 30
= 22 + 30
= 52
Answer(s): 52
