Bag N contains 50-cent coins and Bag P contains 10-cent coins. There are 12 more coins in Bag P than in Bag N. The amount of money in Bag N is 1040¢ more than the amount of money in Bag P. How many total coins are there?
| |
Bag N |
Bag P |
| Number |
1 u |
1 u + 12 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 120 |
Total value of 50¢ coins in Bag N
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Bag P
= 10 x (1 u + 12)
= 10 u + 120
The amount in Bag N is 1040¢ more than Bag P. If another 1040¢ is added into Bag P, both Bag N and Bag P will have the same amounts of money.
50 u = 10 u + 120 + 1040
50 u - 10 u = 120 + 1040
40 u = 1160
1 u = 1160 ÷ 40 = 29
Total number of coins
= 1 u + (1 u + 12)
= 2 u + 12
= 2 x 29 + 12
= 58 + 12
= 70
Answer(s): 70
