Jar W contains 50-cent coins and Jar X contains 10-cent coins. There are 12 more coins in Jar X than in Jar W. The amount of money in Jar W is 360¢ more than the amount of money in Jar X. How many total coins are there?
| |
Jar W |
Jar X |
| Number |
1 u |
1 u + 12 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 120 |
Total value of 50¢ coins in Jar W
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Jar X
= 10 x (1 u + 12)
= 10 u + 120
The amount in Jar W is 360¢ more than Jar X. If another 360¢ is added into Jar X, both Jar W and Jar X will have the same amounts of money.
50 u = 10 u + 120 + 360
50 u - 10 u = 120 + 360
40 u = 480
1 u = 480 ÷ 40 = 12
Total number of coins
= 1 u + (1 u + 12)
= 2 u + 12
= 2 x 12 + 12
= 24 + 12
= 36
Answer(s): 36
