Pouch M contains 50-cent coins and Pouch N contains 20-cent coins. There are 26 more coins in Pouch N than in Pouch M. The amount of money in Pouch M is 20¢ more than the amount of money in Pouch N. How many total coins are there?
|
Pouch M |
Pouch N |
Number |
1 u |
1 u + 26 |
Value |
50¢ |
20¢ |
Total value |
50 u |
20 u + 520 |
Total value of 50¢ coins in Pouch M
= 50 x 1 u
= 50 u
Total value of 20¢ coins in Pouch N
= 20 x (1 u + 26)
= 20 u + 520
The amount in Pouch M is 20¢ more than Pouch N. If another 20¢ is added into Pouch N, both Pouch M and Pouch N will have the same amounts of money.
50 u = 20 u + 520 + 20
50 u - 20 u = 520 + 20
30 u = 540
1 u = 540 ÷ 30 = 18
Total number of coins
= 1 u + (1 u + 26)
= 2 u + 26
= 2 x 18 + 26
= 36 + 26
= 62
Answer(s): 62