Tin Can W contains 20-cent coins and Tin Can X contains 5-cent coins. There are 22 more coins in Tin Can X than in Tin Can W. The amount of money in Tin Can W is 115¢ more than the amount of money in Tin Can X. How many total coins are there?
| |
Tin Can W |
Tin Can X |
| Number |
1 u |
1 u + 22 |
| Value |
20¢ |
5¢ |
| Total value |
20 u |
5 u + 110 |
Total value of 20¢ coins in Tin Can W
= 20 x 1 u
= 20 u
Total value of 5¢ coins in Tin Can X
= 5 x (1 u + 22)
= 5 u + 110
The amount in Tin Can W is 115¢ more than Tin Can X. If another 115¢ is added into Tin Can X, both Tin Can W and Tin Can X will have the same amounts of money.
20 u = 5 u + 110 + 115
20 u - 5 u = 110 + 115
15 u = 225
1 u = 225 ÷ 15 = 15
Total number of coins
= 1 u + (1 u + 22)
= 2 u + 22
= 2 x 15 + 22
= 30 + 22
= 52
Answer(s): 52
