Bag J contains 20-cent coins and Bag K contains 5-cent coins. There are 32 more coins in Bag K than in Bag J. The amount of money in Bag J is 170¢ more than the amount of money in Bag K. How many total coins are there?
| |
Bag J |
Bag K |
| Number |
1 u |
1 u + 32 |
| Value |
20¢ |
5¢ |
| Total value |
20 u |
5 u + 160 |
Total value of 20¢ coins in Bag J
= 20 x 1 u
= 20 u
Total value of 5¢ coins in Bag K
= 5 x (1 u + 32)
= 5 u + 160
The amount in Bag J is 170¢ more than Bag K. If another 170¢ is added into Bag K, both Bag J and Bag K will have the same amounts of money.
20 u = 5 u + 160 + 170
20 u - 5 u = 160 + 170
15 u = 330
1 u = 330 ÷ 15 = 22
Total number of coins
= 1 u + (1 u + 32)
= 2 u + 32
= 2 x 22 + 32
= 44 + 32
= 76
Answer(s): 76
