Tin Can Q contains 50-cent coins and Tin Can R contains 10-cent coins. There are 28 more coins in Tin Can R than in Tin Can Q. The amount of money in Tin Can Q is 680¢ more than the amount of money in Tin Can R. How many total coins are there?
| |
Tin Can Q |
Tin Can R |
| Number |
1 u |
1 u + 28 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 280 |
Total value of 50¢ coins in Tin Can Q
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Tin Can R
= 10 x (1 u + 28)
= 10 u + 280
The amount in Tin Can Q is 680¢ more than Tin Can R. If another 680¢ is added into Tin Can R, both Tin Can Q and Tin Can R will have the same amounts of money.
50 u = 10 u + 280 + 680
50 u - 10 u = 280 + 680
40 u = 960
1 u = 960 ÷ 40 = 24
Total number of coins
= 1 u + (1 u + 28)
= 2 u + 28
= 2 x 24 + 28
= 48 + 28
= 76
Answer(s): 76
