Tin Can F contains 50-cent coins and Tin Can G contains 10-cent coins. There are 20 more coins in Tin Can G than in Tin Can F. The amount of money in Tin Can F is 440¢ more than the amount of money in Tin Can G. How many total coins are there?
| |
Tin Can F |
Tin Can G |
| Number |
1 u |
1 u + 20 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 200 |
Total value of 50¢ coins in Tin Can F
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Tin Can G
= 10 x (1 u + 20)
= 10 u + 200
The amount in Tin Can F is 440¢ more than Tin Can G. If another 440¢ is added into Tin Can G, both Tin Can F and Tin Can G will have the same amounts of money.
50 u = 10 u + 200 + 440
50 u - 10 u = 200 + 440
40 u = 640
1 u = 640 ÷ 40 = 16
Total number of coins
= 1 u + (1 u + 20)
= 2 u + 20
= 2 x 16 + 20
= 32 + 20
= 52
Answer(s): 52
