Jar P contains 50-cent coins and Jar Q contains 10-cent coins. There are 23 more coins in Jar Q than in Jar P. The amount of money in Jar P is 610¢ more than the amount of money in Jar Q. How many total coins are there?
| |
Jar P |
Jar Q |
| Number |
1 u |
1 u + 23 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 230 |
Total value of 50¢ coins in Jar P
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Jar Q
= 10 x (1 u + 23)
= 10 u + 230
The amount in Jar P is 610¢ more than Jar Q. If another 610¢ is added into Jar Q, both Jar P and Jar Q will have the same amounts of money.
50 u = 10 u + 230 + 610
50 u - 10 u = 230 + 610
40 u = 840
1 u = 840 ÷ 40 = 21
Total number of coins
= 1 u + (1 u + 23)
= 2 u + 23
= 2 x 21 + 23
= 42 + 23
= 65
Answer(s): 65
