Bottle B contains only 50-cent coins and Bottle C contains only 5-cent coins. There are 18 more coins in Bottle C than in Bottle B. The amount of money in Bottle B is $2.70 more than the amount of money in Bottle C. Find the total amount of money in both bottles.
| |
Bottle B |
Bottle C |
| Number |
1 u |
1 u + 18 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 90 |
$1 = 100¢
$2.70 = 270¢
Total value of 50¢ coins in Bottle B
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Bottle C
= 5(1 u + 18)
= 5 u + 90
The amount of money in Bottle B is $2.70 more than the amount of money in Bottle C. If another 270¢ is added into Bottle C, the total value of coins in Bottle B and Bottle C will be the same.
50 u = 5 u + 90 + 270
50 u - 5 u = 360
45 u = 360
1 u = 360 ÷ 45 = 8
Total amount in both bottles
= 50 u + (5 u + 90)
= 55 u + 90
= (55 x 8) + 90
= 440 + 90
= 530¢
530¢ = $5.30
Answer(s): $5.30
