Tin Can Z contains only 50-cent coins and Tin Can A contains only 5-cent coins. There are 25 more coins in Tin Can A than in Tin Can Z. The amount of money in Tin Can Z is $1.90 more than the amount of money in Tin Can A. Find the total amount of money in both tin cans.
|
Tin Can Z |
Tin Can A |
Number |
1 u |
1 u + 25 |
Value |
50¢ |
5¢ |
Total value |
50 u |
5 u + 125 |
$1 = 100¢
$1.90 = 190¢
Total value of 50¢ coins in Tin Can Z
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Tin Can A
= 5(1 u + 25)
= 5 u + 125
The amount of money in Tin Can Z is $1.90 more than the amount of money in Tin Can A. If another 190¢ is added into Tin Can A, the total value of coins in Tin Can Z and Tin Can A will be the same.
50 u = 5 u + 125 + 190
50 u - 5 u = 315
45 u = 315
1 u = 315 ÷ 45 = 7
Total amount in both tin cans
= 50 u + (5 u + 125)
= 55 u + 125
= (55 x 7) + 125
= 385 + 125
= 510¢
510¢ = $5.10
Answer(s): $5.10