Coin Box B contains only 50-cent coins and Coin Box C contains only 5-cent coins. There are 11 more coins in Coin Box C than in Coin Box B. The amount of money in Coin Box B is $1.25 more than the amount of money in Coin Box C. Find the total amount of money in both coin boxes.
| |
Coin Box B |
Coin Box C |
| Number |
1 u |
1 u + 11 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 55 |
$1 = 100¢
$1.25 = 125¢
Total value of 50¢ coins in Coin Box B
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Coin Box C
= 5(1 u + 11)
= 5 u + 55
The amount of money in Coin Box B is $1.25 more than the amount of money in Coin Box C. If another 125¢ is added into Coin Box C, the total value of coins in Coin Box B and Coin Box C will be the same.
50 u = 5 u + 55 + 125
50 u - 5 u = 180
45 u = 180
1 u = 180 ÷ 45 = 4
Total amount in both coin boxes
= 50 u + (5 u + 55)
= 55 u + 55
= (55 x 4) + 55
= 220 + 55
= 275¢
275¢ = $2.75
Answer(s): $2.75
