Bottle R contains only 50-cent coins and Bottle S contains only 10-cent coins. There are 15 more coins in Bottle S than in Bottle R. The amount of money in Bottle R is $2.10 more than the amount of money in Bottle S. Find the total amount of money in both bottles.
|
Bottle R |
Bottle S |
Number |
1 u |
1 u + 15 |
Value |
50¢ |
10¢ |
Total value |
50 u |
10 u + 150 |
$1 = 100¢
$2.10 = 210¢
Total value of 50¢ coins in Bottle R
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Bottle S
= 10(1 u + 15)
= 10 u + 150
The amount of money in Bottle R is $2.10 more than the amount of money in Bottle S. If another 210¢ is added into Bottle S, the total value of coins in Bottle R and Bottle S will be the same.
50 u = 10 u + 150 + 210
50 u - 10 u = 360
40 u = 360
1 u = 360 ÷ 40 = 9
Total amount in both bottles
= 50 u + (10 u + 150)
= 60 u + 150
= (60 x 9) + 150
= 540 + 150
= 690¢
690¢ = $6.90
Answer(s): $6.90