Bag R contains only 50-cent coins and Bag S contains only 5-cent coins. There are 24 more coins in Bag S than in Bag R. The amount of money in Bag R is $1.95 more than the amount of money in Bag S. Find the total amount of money in both bags.
|
Bag R |
Bag S |
Number |
1 u |
1 u + 24 |
Value |
50¢ |
5¢ |
Total value |
50 u |
5 u + 120 |
$1 = 100¢
$1.95 = 195¢
Total value of 50¢ coins in Bag R
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Bag S
= 5(1 u + 24)
= 5 u + 120
The amount of money in Bag R is $1.95 more than the amount of money in Bag S. If another 195¢ is added into Bag S, the total value of coins in Bag R and Bag S will be the same.
50 u = 5 u + 120 + 195
50 u - 5 u = 315
45 u = 315
1 u = 315 ÷ 45 = 7
Total amount in both bags
= 50 u + (5 u + 120)
= 55 u + 120
= (55 x 7) + 120
= 385 + 120
= 505¢
505¢ = $5.05
Answer(s): $5.05