Jar E contains only 50-cent coins and Jar F contains only 10-cent coins. There are 15 more coins in Jar F than in Jar E. The amount of money in Jar E is $2.50 more than the amount of money in Jar F. Find the total amount of money in both jars.
| |
Jar E |
Jar F |
| Number |
1 u |
1 u + 15 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 150 |
$1 = 100¢
$2.50 = 250¢
Total value of 50¢ coins in Jar E
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Jar F
= 10(1 u + 15)
= 10 u + 150
The amount of money in Jar E is $2.50 more than the amount of money in Jar F. If another 250¢ is added into Jar F, the total value of coins in Jar E and Jar F will be the same.
50 u = 10 u + 150 + 250
50 u - 10 u = 400
40 u = 400
1 u = 400 ÷ 40 = 10
Total amount in both jars
= 50 u + (10 u + 150)
= 60 u + 150
= (60 x 10) + 150
= 600 + 150
= 750¢
750¢ = $7.50
Answer(s): $7.50
