Jar M contains only 50-cent coins and Jar N contains only 5-cent coins. There are 13 more coins in Jar N than in Jar M. The amount of money in Jar M is $3.40 more than the amount of money in Jar N. Find the total amount of money in both jars.
| |
Jar M |
Jar N |
| Number |
1 u |
1 u + 13 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 65 |
$1 = 100¢
$3.40 = 340¢
Total value of 50¢ coins in Jar M
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar N
= 5(1 u + 13)
= 5 u + 65
The amount of money in Jar M is $3.40 more than the amount of money in Jar N. If another 340¢ is added into Jar N, the total value of coins in Jar M and Jar N will be the same.
50 u = 5 u + 65 + 340
50 u - 5 u = 405
45 u = 405
1 u = 405 ÷ 45 = 9
Total amount in both jars
= 50 u + (5 u + 65)
= 55 u + 65
= (55 x 9) + 65
= 495 + 65
= 560¢
560¢ = $5.60
Answer(s): $5.60
