Tin Can D contains only 50-cent coins and Tin Can E contains only 10-cent coins. There are 12 more coins in Tin Can E than in Tin Can D. The amount of money in Tin Can D is $1.20 more than the amount of money in Tin Can E. Find the total amount of money in both tin cans.
| |
Tin Can D |
Tin Can E |
| Number |
1 u |
1 u + 12 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 120 |
$1 = 100¢
$1.20 = 120¢
Total value of 50¢ coins in Tin Can D
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Tin Can E
= 10(1 u + 12)
= 10 u + 120
The amount of money in Tin Can D is $1.20 more than the amount of money in Tin Can E. If another 120¢ is added into Tin Can E, the total value of coins in Tin Can D and Tin Can E will be the same.
50 u = 10 u + 120 + 120
50 u - 10 u = 240
40 u = 240
1 u = 240 ÷ 40 = 6
Total amount in both tin cans
= 50 u + (10 u + 120)
= 60 u + 120
= (60 x 6) + 120
= 360 + 120
= 480¢
480¢ = $4.80
Answer(s): $4.80
