Tin Can X contains only 50-cent coins and Tin Can Y contains only 10-cent coins. There are 12 more coins in Tin Can Y than in Tin Can X. The amount of money in Tin Can X is $1.60 more than the amount of money in Tin Can Y. Find the total amount of money in both tin cans.
|
Tin Can X |
Tin Can Y |
Number |
1 u |
1 u + 12 |
Value |
50¢ |
10¢ |
Total value |
50 u |
10 u + 120 |
$1 = 100¢
$1.60 = 160¢
Total value of 50¢ coins in Tin Can X
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Tin Can Y
= 10(1 u + 12)
= 10 u + 120
The amount of money in Tin Can X is $1.60 more than the amount of money in Tin Can Y. If another 160¢ is added into Tin Can Y, the total value of coins in Tin Can X and Tin Can Y will be the same.
50 u = 10 u + 120 + 160
50 u - 10 u = 280
40 u = 280
1 u = 280 ÷ 40 = 7
Total amount in both tin cans
= 50 u + (10 u + 120)
= 60 u + 120
= (60 x 7) + 120
= 420 + 120
= 540¢
540¢ = $5.40
Answer(s): $5.40