Bag G contains only 50-cent coins and Bag H contains only 10-cent coins. There are 16 more coins in Bag H than in Bag G. The amount of money in Bag G is $1.20 more than the amount of money in Bag H. Find the total amount of money in both bags.
| |
Bag G |
Bag H |
| Number |
1 u |
1 u + 16 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 160 |
$1 = 100¢
$1.20 = 120¢
Total value of 50¢ coins in Bag G
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Bag H
= 10(1 u + 16)
= 10 u + 160
The amount of money in Bag G is $1.20 more than the amount of money in Bag H. If another 120¢ is added into Bag H, the total value of coins in Bag G and Bag H will be the same.
50 u = 10 u + 160 + 120
50 u - 10 u = 280
40 u = 280
1 u = 280 ÷ 40 = 7
Total amount in both bags
= 50 u + (10 u + 160)
= 60 u + 160
= (60 x 7) + 160
= 420 + 160
= 580¢
580¢ = $5.80
Answer(s): $5.80
