Tin Can X contains only 50-cent coins and Tin Can Y contains only 5-cent coins. There are 14 more coins in Tin Can Y than in Tin Can X. The amount of money in Tin Can X is $1.10 more than the amount of money in Tin Can Y. Find the total amount of money in both tin cans.
| |
Tin Can X |
Tin Can Y |
| Number |
1 u |
1 u + 14 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 70 |
$1 = 100¢
$1.10 = 110¢
Total value of 50¢ coins in Tin Can X
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Tin Can Y
= 5(1 u + 14)
= 5 u + 70
The amount of money in Tin Can X is $1.10 more than the amount of money in Tin Can Y. If another 110¢ is added into Tin Can Y, the total value of coins in Tin Can X and Tin Can Y will be the same.
50 u = 5 u + 70 + 110
50 u - 5 u = 180
45 u = 180
1 u = 180 ÷ 45 = 4
Total amount in both tin cans
= 50 u + (5 u + 70)
= 55 u + 70
= (55 x 4) + 70
= 220 + 70
= 290¢
290¢ = $2.90
Answer(s): $2.90
