Coin Box R contains only 50-cent coins and Coin Box S contains only 5-cent coins. There are 24 more coins in Coin Box S than in Coin Box R. The amount of money in Coin Box R is $2.85 more than the amount of money in Coin Box S. Find the total amount of money in both coin boxes.
| |
Coin Box R |
Coin Box S |
| Number |
1 u |
1 u + 24 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 120 |
$1 = 100¢
$2.85 = 285¢
Total value of 50¢ coins in Coin Box R
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Coin Box S
= 5(1 u + 24)
= 5 u + 120
The amount of money in Coin Box R is $2.85 more than the amount of money in Coin Box S. If another 285¢ is added into Coin Box S, the total value of coins in Coin Box R and Coin Box S will be the same.
50 u = 5 u + 120 + 285
50 u - 5 u = 405
45 u = 405
1 u = 405 ÷ 45 = 9
Total amount in both coin boxes
= 50 u + (5 u + 120)
= 55 u + 120
= (55 x 9) + 120
= 495 + 120
= 615¢
615¢ = $6.15
Answer(s): $6.15
