Jar W contains only 50-cent coins and Jar X contains only 5-cent coins. There are 22 more coins in Jar X than in Jar W. The amount of money in Jar W is $1.15 more than the amount of money in Jar X. Find the total amount of money in both jars.
| |
Jar W |
Jar X |
| Number |
1 u |
1 u + 22 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 110 |
$1 = 100¢
$1.15 = 115¢
Total value of 50¢ coins in Jar W
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar X
= 5(1 u + 22)
= 5 u + 110
The amount of money in Jar W is $1.15 more than the amount of money in Jar X. If another 115¢ is added into Jar X, the total value of coins in Jar W and Jar X will be the same.
50 u = 5 u + 110 + 115
50 u - 5 u = 225
45 u = 225
1 u = 225 ÷ 45 = 5
Total amount in both jars
= 50 u + (5 u + 110)
= 55 u + 110
= (55 x 5) + 110
= 275 + 110
= 385¢
385¢ = $3.85
Answer(s): $3.85
