Bottle R contains only 50-cent coins and Bottle S contains only 5-cent coins. There are 11 more coins in Bottle S than in Bottle R. The amount of money in Bottle R is $2.60 more than the amount of money in Bottle S. Find the total amount of money in both bottles.
| |
Bottle R |
Bottle S |
| Number |
1 u |
1 u + 11 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 55 |
$1 = 100¢
$2.60 = 260¢
Total value of 50¢ coins in Bottle R
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Bottle S
= 5(1 u + 11)
= 5 u + 55
The amount of money in Bottle R is $2.60 more than the amount of money in Bottle S. If another 260¢ is added into Bottle S, the total value of coins in Bottle R and Bottle S will be the same.
50 u = 5 u + 55 + 260
50 u - 5 u = 315
45 u = 315
1 u = 315 ÷ 45 = 7
Total amount in both bottles
= 50 u + (5 u + 55)
= 55 u + 55
= (55 x 7) + 55
= 385 + 55
= 440¢
440¢ = $4.40
Answer(s): $4.40
