Pouch B contains only 50-cent coins and Pouch C contains only 5-cent coins. There are 18 more coins in Pouch C than in Pouch B. The amount of money in Pouch B is $1.80 more than the amount of money in Pouch C. Find the total amount of money in both pouches.
| |
Pouch B |
Pouch C |
| Number |
1 u |
1 u + 18 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 90 |
$1 = 100¢
$1.80 = 180¢
Total value of 50¢ coins in Pouch B
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Pouch C
= 5(1 u + 18)
= 5 u + 90
The amount of money in Pouch B is $1.80 more than the amount of money in Pouch C. If another 180¢ is added into Pouch C, the total value of coins in Pouch B and Pouch C will be the same.
50 u = 5 u + 90 + 180
50 u - 5 u = 270
45 u = 270
1 u = 270 ÷ 45 = 6
Total amount in both pouches
= 50 u + (5 u + 90)
= 55 u + 90
= (55 x 6) + 90
= 330 + 90
= 420¢
420¢ = $4.20
Answer(s): $4.20
