Tin Can Z contains only 50-cent coins and Tin Can A contains only 5-cent coins. There are 14 more coins in Tin Can A than in Tin Can Z. The amount of money in Tin Can Z is $3.80 more than the amount of money in Tin Can A. Find the total amount of money in both tin cans.
| |
Tin Can Z |
Tin Can A |
| Number |
1 u |
1 u + 14 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 70 |
$1 = 100¢
$3.80 = 380¢
Total value of 50¢ coins in Tin Can Z
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Tin Can A
= 5(1 u + 14)
= 5 u + 70
The amount of money in Tin Can Z is $3.80 more than the amount of money in Tin Can A. If another 380¢ is added into Tin Can A, the total value of coins in Tin Can Z and Tin Can A will be the same.
50 u = 5 u + 70 + 380
50 u - 5 u = 450
45 u = 450
1 u = 450 ÷ 45 = 10
Total amount in both tin cans
= 50 u + (5 u + 70)
= 55 u + 70
= (55 x 10) + 70
= 550 + 70
= 620¢
620¢ = $6.20
Answer(s): $6.20
