Bag Z contains only 50-cent coins and Bag A contains only 5-cent coins. There are 11 more coins in Bag A than in Bag Z. The amount of money in Bag Z is $2.15 more than the amount of money in Bag A. Find the total amount of money in both bags.
| |
Bag Z |
Bag A |
| Number |
1 u |
1 u + 11 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 55 |
$1 = 100¢
$2.15 = 215¢
Total value of 50¢ coins in Bag Z
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Bag A
= 5(1 u + 11)
= 5 u + 55
The amount of money in Bag Z is $2.15 more than the amount of money in Bag A. If another 215¢ is added into Bag A, the total value of coins in Bag Z and Bag A will be the same.
50 u = 5 u + 55 + 215
50 u - 5 u = 270
45 u = 270
1 u = 270 ÷ 45 = 6
Total amount in both bags
= 50 u + (5 u + 55)
= 55 u + 55
= (55 x 6) + 55
= 330 + 55
= 385¢
385¢ = $3.85
Answer(s): $3.85
