Coin Box R contains only 50-cent coins and Coin Box S contains only 10-cent coins. There are 13 more coins in Coin Box S than in Coin Box R. The amount of money in Coin Box R is $1.10 more than the amount of money in Coin Box S. Find the total amount of money in both coin boxes.
| |
Coin Box R |
Coin Box S |
| Number |
1 u |
1 u + 13 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 130 |
$1 = 100¢
$1.10 = 110¢
Total value of 50¢ coins in Coin Box R
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Coin Box S
= 10(1 u + 13)
= 10 u + 130
The amount of money in Coin Box R is $1.10 more than the amount of money in Coin Box S. If another 110¢ is added into Coin Box S, the total value of coins in Coin Box R and Coin Box S will be the same.
50 u = 10 u + 130 + 110
50 u - 10 u = 240
40 u = 240
1 u = 240 ÷ 40 = 6
Total amount in both coin boxes
= 50 u + (10 u + 130)
= 60 u + 130
= (60 x 6) + 130
= 360 + 130
= 490¢
490¢ = $4.90
Answer(s): $4.90
