Jar D contains only 50-cent coins and Jar E contains only 5-cent coins. There are 13 more coins in Jar E than in Jar D. The amount of money in Jar D is $1.15 more than the amount of money in Jar E. Find the total amount of money in both jars.
|
Jar D |
Jar E |
Number |
1 u |
1 u + 13 |
Value |
50¢ |
5¢ |
Total value |
50 u |
5 u + 65 |
$1 = 100¢
$1.15 = 115¢
Total value of 50¢ coins in Jar D
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar E
= 5(1 u + 13)
= 5 u + 65
The amount of money in Jar D is $1.15 more than the amount of money in Jar E. If another 115¢ is added into Jar E, the total value of coins in Jar D and Jar E will be the same.
50 u = 5 u + 65 + 115
50 u - 5 u = 180
45 u = 180
1 u = 180 ÷ 45 = 4
Total amount in both jars
= 50 u + (5 u + 65)
= 55 u + 65
= (55 x 4) + 65
= 220 + 65
= 285¢
285¢ = $2.85
Answer(s): $2.85