Jar H contains only 50-cent coins and Jar J contains only 10-cent coins. There are 16 more coins in Jar J than in Jar H. The amount of money in Jar H is $1.60 more than the amount of money in Jar J. Find the total amount of money in both jars.
|
Jar H |
Jar J |
Number |
1 u |
1 u + 16 |
Value |
50¢ |
10¢ |
Total value |
50 u |
10 u + 160 |
$1 = 100¢
$1.60 = 160¢
Total value of 50¢ coins in Jar H
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Jar J
= 10(1 u + 16)
= 10 u + 160
The amount of money in Jar H is $1.60 more than the amount of money in Jar J. If another 160¢ is added into Jar J, the total value of coins in Jar H and Jar J will be the same.
50 u = 10 u + 160 + 160
50 u - 10 u = 320
40 u = 320
1 u = 320 ÷ 40 = 8
Total amount in both jars
= 50 u + (10 u + 160)
= 60 u + 160
= (60 x 8) + 160
= 480 + 160
= 640¢
640¢ = $6.40
Answer(s): $6.40