Tin Can A contains only 50-cent coins and Tin Can B contains only 5-cent coins. There are 12 more coins in Tin Can B than in Tin Can A. The amount of money in Tin Can A is $3.45 more than the amount of money in Tin Can B. Find the total amount of money in both tin cans.
|
Tin Can A |
Tin Can B |
Number |
1 u |
1 u + 12 |
Value |
50¢ |
5¢ |
Total value |
50 u |
5 u + 60 |
$1 = 100¢
$3.45 = 345¢
Total value of 50¢ coins in Tin Can A
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Tin Can B
= 5(1 u + 12)
= 5 u + 60
The amount of money in Tin Can A is $3.45 more than the amount of money in Tin Can B. If another 345¢ is added into Tin Can B, the total value of coins in Tin Can A and Tin Can B will be the same.
50 u = 5 u + 60 + 345
50 u - 5 u = 405
45 u = 405
1 u = 405 ÷ 45 = 9
Total amount in both tin cans
= 50 u + (5 u + 60)
= 55 u + 60
= (55 x 9) + 60
= 495 + 60
= 555¢
555¢ = $5.55
Answer(s): $5.55