Coin Box K contains only 50-cent coins and Coin Box L contains only 10-cent coins. There are 22 more coins in Coin Box L than in Coin Box K. The amount of money in Coin Box K is $1.40 more than the amount of money in Coin Box L. Find the total amount of money in both coin boxes.
|
Coin Box K |
Coin Box L |
Number |
1 u |
1 u + 22 |
Value |
50¢ |
10¢ |
Total value |
50 u |
10 u + 220 |
$1 = 100¢
$1.40 = 140¢
Total value of 50¢ coins in Coin Box K
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Coin Box L
= 10(1 u + 22)
= 10 u + 220
The amount of money in Coin Box K is $1.40 more than the amount of money in Coin Box L. If another 140¢ is added into Coin Box L, the total value of coins in Coin Box K and Coin Box L will be the same.
50 u = 10 u + 220 + 140
50 u - 10 u = 360
40 u = 360
1 u = 360 ÷ 40 = 9
Total amount in both coin boxes
= 50 u + (10 u + 220)
= 60 u + 220
= (60 x 9) + 220
= 540 + 220
= 760¢
760¢ = $7.60
Answer(s): $7.60