Jar P contains only 50-cent coins and Jar Q contains only 10-cent coins. There are 10 more coins in Jar Q than in Jar P. The amount of money in Jar P is $2.20 more than the amount of money in Jar Q. Find the total amount of money in both jars.
| |
Jar P |
Jar Q |
| Number |
1 u |
1 u + 10 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 100 |
$1 = 100¢
$2.20 = 220¢
Total value of 50¢ coins in Jar P
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Jar Q
= 10(1 u + 10)
= 10 u + 100
The amount of money in Jar P is $2.20 more than the amount of money in Jar Q. If another 220¢ is added into Jar Q, the total value of coins in Jar P and Jar Q will be the same.
50 u = 10 u + 100 + 220
50 u - 10 u = 320
40 u = 320
1 u = 320 ÷ 40 = 8
Total amount in both jars
= 50 u + (10 u + 100)
= 60 u + 100
= (60 x 8) + 100
= 480 + 100
= 580¢
580¢ = $5.80
Answer(s): $5.80
