Jar H contains only 50-cent coins and Jar J contains only 10-cent coins. There are 17 more coins in Jar J than in Jar H. The amount of money in Jar H is $1.10 more than the amount of money in Jar J. Find the total amount of money in both jars.
| |
Jar H |
Jar J |
| Number |
1 u |
1 u + 17 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 170 |
$1 = 100¢
$1.10 = 110¢
Total value of 50¢ coins in Jar H
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Jar J
= 10(1 u + 17)
= 10 u + 170
The amount of money in Jar H is $1.10 more than the amount of money in Jar J. If another 110¢ is added into Jar J, the total value of coins in Jar H and Jar J will be the same.
50 u = 10 u + 170 + 110
50 u - 10 u = 280
40 u = 280
1 u = 280 ÷ 40 = 7
Total amount in both jars
= 50 u + (10 u + 170)
= 60 u + 170
= (60 x 7) + 170
= 420 + 170
= 590¢
590¢ = $5.90
Answer(s): $5.90
