Bottle C contains only 50-cent coins and Bottle D contains only 10-cent coins. There are 18 more coins in Bottle D than in Bottle C. The amount of money in Bottle C is $2.20 more than the amount of money in Bottle D. Find the total amount of money in both bottles.
| |
Bottle C |
Bottle D |
| Number |
1 u |
1 u + 18 |
| Value |
50¢ |
10¢ |
| Total value |
50 u |
10 u + 180 |
$1 = 100¢
$2.20 = 220¢
Total value of 50¢ coins in Bottle C
= 50 x 1 u
= 50 u
Total value of 10¢ coins in Bottle D
= 10(1 u + 18)
= 10 u + 180
The amount of money in Bottle C is $2.20 more than the amount of money in Bottle D. If another 220¢ is added into Bottle D, the total value of coins in Bottle C and Bottle D will be the same.
50 u = 10 u + 180 + 220
50 u - 10 u = 400
40 u = 400
1 u = 400 ÷ 40 = 10
Total amount in both bottles
= 50 u + (10 u + 180)
= 60 u + 180
= (60 x 10) + 180
= 600 + 180
= 780¢
780¢ = $7.80
Answer(s): $7.80
